"Leetcode POTD 1400(Medium) : Construct K Palindrome Strings"
Approach Summary:
Edge Case Handling:
If the length of the string s is less than k, it is impossible to form k palindromes, so return false. If the length of the string s is equal to k, each character can be placed in its own palindrome, so return true.
Character Frequency Count:
Use a frequency array (freq) to count the occurrences of each character in s.
Count Odd Frequencies:
Traverse the frequency array to count the number of characters that appear an odd number of times (oddCount).
Key Observation:
A character with an odd frequency must appear in its own palindrome (e.g., for "aaaab", the b must be a separate palindrome). Therefore, the number of odd-count characters (oddCount) determines the minimum number of palindromes required.
Final Check:
If oddCount greater than k, it's impossible to form k palindromes, so return false. Otherwise, return true, as we can distribute the even-count characters among the k palindromes.
Key Insight :
The approach leverages the relationship between odd-frequency characters and palindromes:
Odd-count characters determine the minimum number of palindromes required.
Even-count characters can be freely distributed across the palindromes.
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