S(t)=t³-6t² 9t
i. v(t)=3t²-12t 9
ii. a(t)=6t-12
iii. At rest, v(t)=0
3t²-12t 9=0
t²-4t 3=0
(t-1)(t-4)
t = 1s, or t = 3s
iv. On motion, v(t)>o
So we say
3t²-12t 9>0
Factorising again, we will arrive at
(t-1)(t-3)>0
So the particles move forward at
"t<1 or t>3"
A particle moves along a straight line, and its position at time t sec is given by:
s(t)=t³-6t² 9t
Find the velocity and the acceleration of the particle at any time
Find the time(s) when d particle is at rest.
Find the time intervals when the particle is moving forward.
GM guys